Ho trovato una pagine interessante per i calcoli relativi alle barlow
http://astunit.com/astunit_tutorial.php?topic=barlowQuesta formula per esempio
M = 1 + (x/f) = 1 + (75 + 80)/75 = 3.07
Calcola il potere moltiplicatore di una barlow 2x con focale 75mm allontanata di 80mm
Raffaello non e' che per caso bisogna aggiungere un 1+ ?
Copio e incollo la parte piu' interessante
Calculating Barlow magnification:
F = focal length of objective or primary
f = focal length of Barlow [1]
J = joint focal length (effective focal length)
d = separation of Barlow and original focal plane (objective focal plane)
x = separation of barlow and new focal plane (eyepiece focal plane)
M = amplification of Barlow
J = (F×f)/(f-d) ...(1) (combined lens formula)
M = J/F ...(2) (by definition)
= f/(f-d)
The separation of the Barlow and the new focal plane can be calculated from M and f:
x = f×(M-1) ...(3)
...from which we get :
M = 1 + (x/f)
One of the connotations of all this is that a Barlow that is its own focal length inside the original focal plane (d) will produce a collimated (i.e. parallel) beam. Another is that d only needs to change slightly to bring about significant variations in x (play with the formulae — or your telescope — to see this) [2].
Finding the approximate Focal Length of a X2 Barlow
The simplest way to do this is as follows:
Locate the location of the field stop inside an eyepiece.
Mark this position on the outside of the eyepiece barrel.
Locate the position of the middle of the lens grouping in the Barlow.
Mark this position on the outside of the Barlow barrel.
Insert the eyepiece into the Barlow.
Measure the distance between the two marks. This is the approximate focal length of the Barlow.
Note: This can only be approximate as the distance of the field stop from the "shoulder" of the eyepiece barrel varies from eyepiece to eyepiece. This is why the marked amplification factor of a Barlow can only be nominal.
Worked examples:
1. Based on Separation of Eyepiece Focal Plane and Barlow
Let us take a 75mm focal length x2 (nominal) Barlow used at its designed amplification. (f = 75mm, M = 2)
M = 1 + (x/f)
δx = f(M - 1) = 75(2 - 1) mm = 75mm
This relationship (the separation of Barlow and the new focal plane is equal to the focal length of the Barlow) holds for any x2 Barlow.
Let us now use the old trick of increasing Barlow amplification by inserting a star diagonal between the eyepiece and Barlow. Assume that the star diagonal adds 80mm to the optical path.
M = 1 + (x/f) = 1 + (75 + 80)/75 = 3.07
i.e. a nominal x2 Barlow has become an (approximate) x3 Barlow. Similarly, the introduction of a 150mm extension tube instead of the diagonal will give an amplification factor of x4.